Structural Shear Analysis: A Full Iteration Approach

Oct 17, 2023
1 minute read
BLOG BRIDGE INSIGHT

Solving the previous example from full iteration

 

Now it’s time to solve the previous example from full iteration. For simplicity, interaction with flexure is not considered. In other words, it is assumed that the status is in a pure shear condition which rarely exists in the real world.

 

Assume that both tensile and compression reinforcements are 3-#11 (4.68 in2) and stirrups are 2-#3@6 in.

 

Detailed calculation is only shown for ε1=0.002 case.

 

Step 1) choose ε1=0.002

 

Step 2)

 

Step 2)

Step 3)

 

Step 3)

Step 4) estimate θ=36.30°

 

Step 5) estimate fv=35.75 ksi

 

Step 5) estimate fv=35.75 ksi

Step 6)

 

From vertical equilibrium,

 

From vertical equilibrium

From Mohr’s circle,

 

From Mohr’s circle,

 

From Mohr’s circle[2]

 

From definition,

From definition

or

 

From definition or

Step 7)

 

Step 7)

Step 8)

 

Step 8)

Step 9)

 

Step 9)

Step 10) 

 

Step 10) 

Step 11)

 

Step 11)

Step 12)

 

Step 12)

 

Repeat Steps 5) to 12) as required.

 

Step 13)

 

Step 13)

Otherwise, repeat Steps 4) to 13) as required.

Step 14)

 

Step 14)

Otherwise, reduced f1 and repeat Steps 6) to 14) as required.

 

Otherwise, reduced f1 and repeat Steps 6) to 14) as required

Similar calculations can be done for other values of ε1. It would be helpful if the following strain cases are included as the minimum, 1) cracking strain, 2) stirrup yield strain, and 3) concrete crush strain.

 

Shear response summary

 

Shear response summary[1]

Shear response summary[2]

For this analysis, we can get some useful information.

 

For this analysis, we can get some useful information.

ε1 vs θ (°)

With the increase of principal strain ε1, the crack angle θ tends to decrease.

 

With the increase of principal strain ε1, the crack angle θ tends to decrease.

ε1 vs Vc, Vc+Vs (kips)

With the increase of principal strain ε1, resistance from concrete Vc tends to decrease, but resistance from reinforcement tends to increase. The maximum resistance occurs at the yielding points.

 

With the increase of principal strain ε1

ε1 vs f1, f2 (ksi)

With the increase of principal strain ε1, principal tensile stress f1 tends to decrease, but principal compressive stress f2 tends to increase.

 

Conclusion

 

From the full iteration analysis, we can see that the shear resistance is around Vc+Vs=200 kips, ?Vn=180 kips which is larger than the demand Vu=157 kips. Considering we reduced stirrup spacing from a maximum of 7.7 in. to 6 in., these results look very reasonable. Also, the crack angle θ=36.30° at the stirrup yielding condition is close to θ=36° from the design table.

 

About the Editor
Seungwoo Lee PhD, P.E., S.E.
Senior Supervising Engineer at WSP USAs (Tampa, FL)

He is a Senior Supervising Engineer with a high level of expertise in the design and analysis of suspension bridges. He has a solid fundamental understanding of structures and can apply his knowledge exceptionally well to the design and analysis of highly complex structures. He is also a strong communicator, able to identify and distill the key information that is relevant to the task at hand and present it in a clear and quickly understandable manner.

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